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Vikrant
- Rate €8
- Response 1h
€8/h
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- Maths
- Algebra
- Trigonometry
- Arithmetic
- Geometry
Hello!My Name is Vikrant .I am 22 years old.i live in aligarh in UP.Recently i Have completed my graduation. I Have been teaching for four years. I am special for maths.
- Maths
- Algebra
- Trigonometry
- Arithmetic
- Geometry
Lesson location
About Vikrant
Sure ,as you know my name is vikrant.i am from uttar pradesh.i have completed my bachelor of Arts from Dr.bhimrao ambedker University agra.i have four years experience of teaching students of all levels. I have teach as a maths teacher
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About the lesson
- Primary
- Junior Cycle
- Transition Year
- +9
levels :
Primary
Junior Cycle
Transition Year
Fifth Year
Sixth Year
Adult education
Bachelor's degree
Master's degree
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Barrister-at-law degree
- English
All languages in which the lesson is available :
English
Find the mean of the 32 numbers, such that if the mean of 10 of them is 15 and the mean of 20 of them is 11. The last two numbers are 10.
Solution: The given mean of 10 numbers = 15
So, Mean of 10 numbers = sum of observations/ no. of observations
15 = sum of observations / 10
Sum of observations of 10 numbers = 150
Similarly, Mean of 20 numbers = sum of observations/ no. of observations
11 = sum of observations / 20
Sum of observations of 20 numbers = 220
Hence, Mean of 32 numbers = (sum 10 numbers + sum of 20 numbers + sum of last two numbers)/ no. of observations
Mean of 32 numbers = (150 + 220 + 20 ) / 32 = 390 /32 = 12.188
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Rates
Rate
- €8
Pack prices
- 5h: €40
- 10h: €80
online
- €8/h
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